MATH SOLVE

3 months ago

Q:
# A father is four times as old as his son now. If 5 years later the father is 3 times as old as his son's age. What are their present ages

Accepted Solution

A:

Answer:The Present age of father is 40 years The Present age of son is 10 years Step-by-step explanation:Given as :Let the age of father = F yearsThe age of son = S yearsAccording to question F = 4 × S ......... 1And ( F + 5 ) = 3 × ( S + 5 ) F + 5 = 3S + 15 Or, F - 3S = 15 -5Or, F - 3S = 10 ......... 2From Eq 1 and Eq 2 4S - 3S = 10 ∴ S = 10 years Put the value of S in eq 1So , F = 4 × S = 4 × 10 ∴ F = 40 years Hence The Present age of father is 40 years And The Present age of son is 10 years Answer